Tag Archives: online Algebra tutors

Explore the Concepts of Math With Online Tutoring

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Concepts of Math

High radical questions and amicable solutions are the target of present educational set up to highlight the essential scope of in-depth education in whatever subject you touch. Hence, it is not an easy task to solve an assignment problem or complete a homework topic. You need special attention and get stuck up now and then without being able to move ahead. A friend, philosopher and guide, who is an expert tutor in all areas of your learning sits by and says’ hi’ to you, you could sigh relief and feel ‘Yep’! ‘Everything is fine’! – Don’t worry. Online services are there as your best support who could rescue you at the eleventh hour from the tying hazards of educational difficulties.

Whom to approach?

Well, that is a good question. Private tutors are there, conventional masters could overview you, your school authorities may pose their suggestions to you- aside from these, one great supporter who could enter your heart, wait for your nod and it is only your one’ yes’ that could motivate so many’ yeses’ from him-your online tutor, who can work your Mathematical sums, Biology lessons, questions in History, problems in Physics, equations in Chemistry and proof read your essays in English.

With the learning technology and high speed internet services, he demands only free mobile apps from you or a computer or laptop to share his online classroom with you. Not only does he provide solutions for all your assignments and homework help, he extends his service with sharing the docs, allowing you to store them for future use, establishing sustained real-time examples of all subjects and throwing light on deeper aspects of your learning a particular subject. He sticks to the Common Core Standards, not to create trouble with your school curriculum. Definitively it is, you feel a quality experience with a boosted morale to enter your school, with a tendency to achieve better grades from B to A in any subject possible.

Want to get help in Math?

Math is an over imposing strict master for 90 % of the learning candidates at any grade or academic level. Not that a kindergarten alone dreads Math, even an SAT sitter finds the same. Only a help from math tutoring online could remove this panic of Math from you with their enhanced quality service and readymade solutions. E- Tutors in Math furnish videos and books that could dissect complicated Mathematical concepts with deep insights and get you an intense probe into the root theories of Math.

The mini lessons, worksheets and online tables offered by Online Math Tutor are any time help to tackle the problems at the last moment with no impediment and finish off the work on time. A gradual, step by step explanation of Linear Programs, converting Fractions into Decimals and various other aspects of Math do save the student’s time, energy and relieve him of the mental agony of struggling with answers.

Want Algebra Help?

Algebra is a basic concept that demands a deep foundation to become strong in Mathematical analysis. You need not worry with your difficult areas in Pre Algebra, Algebra1 or Online algebra tutors are ready with the solvents and examples to your queries in Exponents and Radicals, Function and Graphs, Factoring, Equations and Inequalities.

9 Must Know Methods for Solving Math Problems

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Math has many topics and there are various kinds of questions related to each given topic. To solve a given math problem different kinds of methods and formulas can be used. Today, we will try to learn and understand 9 most basic and useful methods utilized while solving Math questions. Let us get started:

1. Method for calculating the LCM (Least Common Multiple)

Finding the least common multiple for the given numbers. I am pretty sure most of you have observed that LCM are part of problem solving for no matter which math topic you are working on. We need to calculate the LCM’s in simple topics like fractions, decimals and they may be also required to be calculated while solving questions in algebra, geometry and many more. Follow the example below:

What is the LCM of the two numbers 6 and 15?

For finding the LCM (least common multiple) first write the multiples for the given numbers.

Remember the 6 times table? Yes! They are all the multiples of number 6, so you have 6, 12, 18, 24, 30…. .

Now the 15 times table, don’t worry you need to check only till you get the common multiple.

So you have 15, 30, 45……………..

Did it strike a bell? Well look below for more clarity:

LCM

Hence the LCM for 6 and 15 equals to 30. (Sometime there can be more than one common multiple, always pick the least number as the LCM.)

2. Method for calculating the GCF (Greatest Common Factor)

Following the LCM is another interesting method in number theory. You guessed it right! The GCF (The greatest common factor.) For finding the GCF the Tree diagram method is very common. Here is a question: Find the GCF for the numbers 21 and 35? The first step is to write the tree diagram for 21 and 35. Try to follow the tree diagram below: GCF Using this tree method, you will get 21 = 3 x 7 and 35 = 5 x 7. (Note: 1 is always a factor for any given number.) Here 7 is the common factor for 21 and 35, which can be written once as its repeating in both the numbers. The Greatest common factor includes the remaining factors from both the numbers as well. Do not forget to include the 5 and 7. Hence GCF for 21 and 35 equals 3 x 5 x 7 = 105. After the LCM and the GCF, let us look at the method for changing the decimal numbers into fractions. Follow the example carefully:

3. Method of converting the decimal numbers into fractions

Convert the given decimal number 0.3 into a fraction. Here given to us is a decimal number. Count the number of decimal places. The number 0.3 has only one decimal place. Now while changing into a fraction multiply the numerator and the denominator by 10 for every decimal place. Here, since there is only one decimal place multiply by 10. Try to follow the diagrams below: decimal numbers into fractions Hence 0.3 can also be written as 3/10.

4. Method for solving Unit and Total Price word problems

Time to solve a work problem on price and money:

Anna and Ben went to a park. Anna brought 3 balloons and Ben brought 2 balloons. Find the total amount of money spent if each balloon costs $0.25.

For the given question you need to first calculate the total number of balloons Anna and Ben brought = 2+ 3 = 5.

Now comes the crucial point the decimal multiplication. Each balloon costs $0.25, so 5 balloons costs 5 x 0.25. Need help? Look at the diagram below:

Total Price

Hence the total price spent by Anna and Ben = $ 0.75.

Well problem solving is incomplete without equations. The next few methods will help you solve equations.

5. Method for solving one step equation using Addition

Find the value of y in the equation y – 6 = 12?

In the given equation 6 is subtracted from y. So the reciprocal operation needs to be applied to the equation. Add 6 on both sides of the given equation. This gives:

one step equation using Addition

Hence, the value of y = 18.

6. Method for solving one step equation using Subtraction.

Find the value of x in the equation x + 30 = 150? In the given equation 30 is added to x. So the reciprocal operation needs to be applied to the equation. Subtract 30 on both sides of the given equation. This gives: equation using Subtraction Hence the value of x = 120.

7. Method for solving one step equation using Multiplication

Find the value of y in the equation y/2 = 7? In the given equation y is divided by 2. So the reciprocal operation needs to be applied to the equation. Multiply by 2 on both sides of the given equation. This gives: equation using Multiplication Hence the value of y = 14.

8. Method for solving one step equation using Division

Find the value of x in the equation 5x = 45.

The given question has the equation with one variable x. I believe, by now did you get a hold of this method? The reciprocal operation of multiplication is division. Divide both sides of the equation by 5. This gives:

equation using Division

Hence the answer to the given equation is x = 9.

9. Method for solving Expressions using substitution

Now, what if there is an expression with more than one variables and you need to find the value of the expression. Here is what needs to be done:

Evaluate the value for the expression 4x – y, when x = 1 and y = 2.

Here for this question the method of substitution can be applied. You are given the value of x = 1 and y = 2. Hence substitute the values in the given equation to solve the question.

Not really sure how! Try to follow the diagram below:

Expressions using substitution

Much better, isn’t it! So after substitution here is how the expression will look like: 4(1) – 2 = 4 – 2 = 2. Hence the solution = 2.

We are not done yet! These were just few methods to get you started on solving math problems. To know more chat with a live Math tutor online and get more interesting details about the topic.

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Tutor Pace Presents High School Algebra Tutors For Better Subject Insights

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Algebra is always a threatening master with intricate concepts and topics.You need to know Algebra topics with deep insights to breeze through High School Algebra. Exponents, Scientific Notation or Factoring could tap you on your head at any time and send you out of the circle of renowned scorers in Algebra.

High School Algebra TutoringWell, to start with,

What is Algebra?

Algebra is a branch of Math that uses letters as substitutes for numbers, to say it in simple terms. Moving from Arithmetic to Algebra, looks like this:

In Arithmetic: 3 + 4 = 3 + 4

In Algebra it is: x + y = y + x.

Very simple to say but when it moves on and reaches high school level, students need to concentrate on great many topics like Exponents, solving equations, scientific notations and so on.

Roots of numbers and radicals in Grade 10 could be difficult to understand. Let us see one example

Write 128 and 32 as product/powers of prime factors:

128=27, 32=25 hence
root

 

 

 

Or one more problem like

Factorize the following:
2xy – 12y

Visualize this as 2*x*y – 2*6*y.

What is common to both terms? Answer is 2

What is left in both terms once the 2 is removed?

Answer is xy – 6y

Answer is: 2(xy – 6y) Bottom of Form

When such solutions are handed ready-made and with explanations in simple terms, no high school student could find tremors in doing homework problems in Algebra and would have great hopes of scoring well in the subject. Tutor Pace renders easy solutions to even the most difficult topics in High school Algebra through its High School Algebra Tutors and helps students gain confidence in acing the subject and getting through the topics with an easy sway.

Tutor Pace offers online High School Algebra Tutoring as a source of support for parents who panic at the thought of their kids struggling with Algebra sums with lowering grades. Such parents find our tutoring services as a solace for the guaranteed support we render in various Algebra topics like Simplify Radical Expressions, Add and Subtract Radical Expressions and so on. Ours is a network of experienced tutors who give their best to shape the basic skills of high school Algebra in students and help them do their lessons with ease of mind and deft methods.

High School Algebra Homework Help from Tutor Pace is for the relief of parents and students who find the homework schedules hectic at high school level. With the crucifying demands of all subjects and the oncoming competitive exams, it is but natural for kids to lose heart and for parents to panic and become anxious over the results of the ongoing tests and exams. Leave the responsibility in the hands of online Algebra tutors of Tutor Pace and enjoy a calm and balanced mind to await Algebra exams with the best subject prep possible and ace Algebra for exceptional scores.

It is an assured atmosphere of success in the personalized virtual classes of Tutor Pace with excellent explanations for the queries posed by the students to our tutors. Avail online High School Algebra tutoring services from Tutor Pace for guaranteed success in high school Algebra and land on the portals of college with great confidence.