Top 5 Things That You Must Seek In Online Algebra Tutors

Most parents with their youngsters in school always remain willing to extend some assistance with their homework assignments. In any case, with math subjects like variable based math, a guardian’s earnest attempts may not be very sufficient. Handling math comparisons and equations that substitute numbers with letters and images may take more than they could possibly deal with.

algebra

To the greatest advantage of their kid’s efforts, a guardian must leave variable based math teaching to an expert online Algebra tutor who is more acquainted with this specific sort of critical thinking and approach. During a time where youngsters may be more equipped for using a portable PC than their guardians, it may be valuable to look for the administrations of an online variable based math mentor.

Things being what they are, whether you are simply such a guardian and are considering picking this specific alternative, it would be a good idea to know some crucial things when surfing through the several internet coaching administrations that are accessible these days online.

Five of the most essential things to consider when searching for an online variable based math guide for Algebra homework help are:

Accreditations

Does the mentoring administration have a decent reputation? Are the mentors who work for this administration have the information base that is required to teach the subject effectively? In the event that the guide has a BA degree in Geography, then the mentoring knowledge may not be entirely as compelling as somebody with a decent background in math and sciences. Does the tutor have any genuine instructing knowledge? Coaches may be knowledgeable yet unless they know the better purposes of performing the activity may get to be useless.

Online Tutoring Tools

Does the online administration offering mentoring have the right kind of innovative teaching tools to simplify the learning procedures? Will your youngster have the capacity to connect specifically with their mentors? Will he or she have the capacity to make inquiries about their coach? Administrations that give access to their learners to their coaches through chat rooms will deliver better results.

Security Assurances for your Child

Online tutoring administrations that give direct access to guides and learners are the favored approach to go. However, folks ought to ask for strong character references of their youngster’s guide. The service providers need to guarantee the people that all the suitable individual verification are set up before they carry their mentors into contact with your young ones.

The Teaching Style

Parents should unforgettably raise queries with online tutoring service provider on how the guides will convey the information their child needs to learn. Each kid adapts diversely and an online variable based math guide must have the adaptability to change their specific style of educating to address the issues while extending algebra assignment help.

Service charges

What prices will the service provider charge? As a customer, you have to take a comprehensive look at all the alternatives out there before settling on an online tutor. Just through a little bit of research work on the internet, you will be able to get the best services at simply incredible prices.

Get Algebra Homework Help To Solve Word Problems With Ease

Word problems may sound terrifying and may intimidate at the first glance. The trick to working with them is quite simple however. Just read through the problem statement and work on writing it down in the form of equations that has variables. There are many kinds of word problems and being conversant with the various types is important to approaching tests confidently.

algebra problem

The most common word problems are:

  • Age related problems
  • Average problems
  • Coin/Stamp/Ticket problems
  • Consecutive Integers, digits and other integer problems
  • Interest problems
  • Fraction problems
  • Geometry word problems and motion related problems
  • Mixture, number sequences, ratios, proportions and work problems

Notice the keywords that signify the operation to be performed

Most word problems contain certain keywords that indicate as to which operation needs to be performed. For instance, when the case is addition, words such as added to, sum, total, increased to, etc are employed. While for subtraction, removed, less than etc is used. Identifying this can help you write down the equation properly. Students today turn to an online algebra tutor for help and they usually recommend such tips as they have proven to be effective and help the students construct the equations quickly.

Jot down relevant information before solving the problem

As and when you read the question, if there is anything at all that strikes you as important or as having some significance, write down irrespective of whether you can make sense out of it or not. This will in turn help you in getting a clearer picture and aid you in problem solving. It is always important to jot down relevant info while reading any problem whether in algebra or any other branch of math for it ensured easier problem solving.

There can be no substitute to practice

Practice makes perfect is the time tested theory and algebra is no exception to it. Practicing as many problems as you can is important and ensures that you are well prepared for exams and help you score better. When you are given an assignment, seek algebra assignment help online to get your doubts clarified and work out the problems on your own. This helps you tackle your tests head on!

Summary

Algebra is a popular subject where students seek professional help to understand underlying concepts and get help with their homework and assignments. The above mentioned tips outlay a methodical approach to problem solving, particularly working with algebra word problems. Following these tips is a sure shot way to success when it comes to solving algebra word problems which are an integral part of the tests.

Math For Advanced Level; Algebra Geometry And Calculus Advanced

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Math is a combination of many branches such as Algebra, Geometry and Calculus, but math does not quite stop right there, we have levels to each branch of math such as beginners and advanced. The advanced level math usually needs more attention and practice to master it. If you are confident with the basics and know all your formulas then the advanced level math is the next step to beginner math topics. Today let us look at different advanced level math questions in areas such as Algebra, Geometry and Calculus.

Advanced level Algebra

Algebra consists of different algebraic expressions and equations. Algebra has different kind of questions to solve. Mentioned below are few such questions which will give you an idea about how to use the basics of algebra to solve advanced level questions:

Solving linear equations with one variable:

Find the value for x in equation 4 (2x – 3) = 5 (2x – 8)?

Here the unknown variable is x. Since there are numbers in front of the brackets, distribute the numbers as shown below:

math1

Here we have x on both sides of the equation, bring all like terms to the same side of the equation and solve for x.

math2

As show above the equation reduces to 2x = 28. Divide by 2 on both sides of the given equation. This gives x = 14.

Did you follow the solution to the question above? Now let us look at solving an inequality. Solving inequities play an important role in algebra. An inequality is where there is a comparison and is represented by a less than or greater than symbol. The solution to the inequality are usually represented on a number line, so as to represent all the possible values for the variable. Follow the given example below:

Solve the given inequality 3 (2 x + 8) > 24?

Look at the question we have greater than symbol here. You have to solve for the unknown variable x and find all the possible solutions for it. For the given question above, divide both sides of the equation by 3 as show below:

math3

Now the inequality is reduced to the form 2x + 8 > 16. The next step is to solve for x. follow the steps below:

math4

The inequality is now reduced to x > 4. Look at the symbol separating x and 4 it’s a greater than sign not greater than equal to. This implies that the number 4 is not included in the solution. Hence the solution of x contains all the values greater than 4 such as 5, 6, 7, 8…….. This can be represented on a number line as show below:

math5

The advanced level algebra consists of many other subtopics such as quadratic equations, solving two variable equations using substitution and elimination methods and many more. The key to success for solving all such questions is practice and knowing the basics of Algebra.

Advanced level geometry:

After algebra let us look into geometry and some sample question. Geometry is one of the favorite topic for all the students especially when you are in the elementary school, it could be because of learning different kinds of shapes. But geometry does not quite stop there, as you go to the higher grades you need to tackle the advanced level. Let us look at two examples on how the basics of geometry can be helpful to solve the advanced level geometry question.

 Find the area between the two shapes for the given geometric figure:

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The given diagram is a square inscribed in a rectangle. Let us recall the formula for the area of the rectangle = length x width. Using the formula, the area of the rectangle = 10 x 8 = 80 square inches.

Now the area of the square = side x side. Using the formula, the area of the inner square = 4inches x 4inches = 16 square inches.

The area between the two geometric figures is obtained by the difference in the areas.

Hence, the area = (80 – 16) square inches = 64 square inches.

Did you follow the solution? Great! The next question you will see how the sum of the angles can be used to find the missing angles of the triangle.

The sum of all interior angles of a triangle = 180 degrees. This fact is very commonly used in solving many geometrical questions. Knowing the angle measures helps you classify the different kinds of triangles such as equilateral, scalene, and isosceles.

In the given diagram, find the value of v and the angles of the triangle. Classify the triangle?

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Sum of all the angles of a triangle = 180 degrees.

Adding all the angles of the triangle v + 2v + 60 = 180. This gives 3v + 60 = 180.

Solve for the variable v, follow the steps below:

math8

The angles of the triangle are v = 40 degrees, 2v = 2 (40) = 80 degrees and the third angle is 60 degrees. Therefore, the angles of the triangle are 40, 60 and 80 degrees. Since all the angles of the triangle are different. The given triangle is a scalene triangle.

Advanced level Calculus

The next branch of mathematics which is very important and plays a major role in high school and college level math is calculus. The students are expected to know pre-calculus before stepping into calculus or advanced calculus. Calculus starts off form the basics of functions, domain, range and steps into differentiation and integration, which are the advanced level topics.

Let us take a quick look at few solved calculus questions:

Find the derivative to the function f (x) = 3x3 – 5x2 + 10?

Here before finding the derivative of the given question there are some formulas of derivatives which are expected to be known. Learn from the diagram below:

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Did you recall the formulas? Now apply the power rule to 3x3 and -5x2. Since 10 is a constant the derivative will be zero. Take a look at the diagram below:

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The answer f’(x) = 9x2-10x.

Taking a step forward, let us solve a derivative question involving logarithms and exponential functions.

Find the derivative of the function f(x) = x5 + 2ex + 3log x?

For the given question you can apply the power rule to x5, exponential rule for 2 ex and logarithmic rule for 3 log x. Use the formulas as mentioned in the diagram below:

math11

Applying the formulas to the given function:

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Hence the solution f’(x) = 5x4 + 2ex + 3/x.

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How To Apply Concepts Of Algebra To Geometry?

In this particular article we have focused on a few properties determined in Geometry utilizing Algebra mathematics. You can definitely consult some kind of math homework help to know more in depth.

Concepts Of Algebra To Geometry

Give us a chance to take the case of a straight line. What do we watch? A straight line meets the X-Axis or the Y-Axis in any one among the four quadrants. A line can be plotted hanging some place in the center, yet dragging it whichever way would make it unquestionably meet in one of the four quadrants. Which properties are held by a straight line? A straight line converge either the y or x axis with a point. If this line makes a point of 90 degrees with the X-Axis, then it is parallel to the Y pivot or it is the Y-Axis itself. On the other hand if this line makes a point of 90 degrees with the Y-Axis then it runs parallel to the X pivot or can be the X-Axis itself.

Let us assume a point on hold as (X, Y), and explore the relationship in the middle of X and Y. Let us extend the point to the X and the Y pivot separately. Let the line converge the X-Axis at (C1, 0) and the Y-Axis at point (0, C).

Assuming a right triangle between the beginning and the two convergence focuses on the X and the Y axis where the straight line meets the two pivots. Let theta be the point made by the straight line and the X-Axis. By definition tan(theta) is equivalent to stature/base of a right triangle. So tan(theta) for this situation is only C/C1.

At some other point (X, Y) on the straight line tan(theta) is equivalent to Y/C1-X.

Likening both we get Y/C1-X= C/C1 so Y = C(C1-X)/C1 = – XC/C1 + C.

Since theta is the inside point made by the straight line with the X-Axis, the outside edge is equivalent to PI-Theta. Likewise, tan(theta) = – tan(PI-theta).

So if takes after that – C/C1 = tan(exterior point).

Y = tan(exterior point) * X + C. This is only the prevalent mathematical statement Y = M*X + C.


Presently apply some rudimentary variable based math to infer the Pythagoras hypothesis.

Consider a right triangle at the beginning with directions (0, 0), (a,0) and(0,b)

The hypotenuse’s length is only sqrt (a*a + b*b).

This is only the squares’ entirety of the other two sides, which is according to the Pythagoras hypothesis.

Now move to a circle, what are the properties of a circle. Any point along the circle is at a separation of r from the focal point of the circle. Let the focal point of the circle be at the birthplace. Take a point (X, Y) situated at any place on a circle. So the separation of that indicate the middle is sqrt(X *X + Y * Y) which is equivalent to r the span’s length.

So the mathematical statement of a circle is sqrt(X*X + Y*Y) = r or X*X + Y*Y = r*r.

By mixing Geometry with Algebra is presently termed as co-ordinate geometry.

Summing up things…

Both Geometry and Algebra are different branches of Mathematics. However, both share a strong relation in the form of Co-ordinate Geometry that needs to be learned through expert online math tutoring by consulting a well versed online math tutor. Let us know if you have more to share.

Become An Amazing Math Tutor: The Secret To Metal Math

Math is a very interesting and innovative subject, we start learning it from a very young age and use it all our lives. The secret to metal math can be understood when you want to solve questions much faster and efficiently. This can be applied for both the students and tutors. Often we wonder why the same question is solved by different people in different ways. This is the beauty of math, there are many ways and approaches to get to the same answer. One method can take more time and many steps whereas another method can take less time and fewer steps to reach the final answer. The thing to realize here is all the different approaches are right and you can follow which ever method best suits your ability to understand the given question.

Let us now take a look at some mental math tricks which will help you while solving different math homework help questions.

While changing the percentages to fractions, divide by 100 and for changing a given fraction to percentage multiply by 100. Here are some examples:

Betty went to trekking with her friends. She drank 75% of the protein shake she brought with her after trekking for 3 hours. What fraction of the protein shake does she have left?

For the above question we are given that 75% of the protein shake is finished. This implies the remaining amount is equal to 100% – 75% = 25%.

Therefore, the amount of protein shake Betty has = 25%. For converting the given percentage into a fraction divide by 100. math help 1 Hence Betty still has 1/4 of the protein shake remaining during her trekking.

Did you find the example quite interesting? Now let us look at another example for changing fractions to percentages.

Samuel finished 1/5 of his homework. What percentage of his homework is still to be completed?

Here you are given that 1/5 of the homework is completed. This implies the amount of homework to be completed is 1 – 1/5 = 4/5.

Now for converting the fraction into a percentage multiply by 100. Follow the diagram given below and try to visualize the calculations mentally:

math help 2

This method mentioned above is very useful because percentage are used almost in every branch of mathematics. Let us look at some quick applications of what we have just learned:

Percentage to fraction:

math help 3

The above examples are for percent to fractions which can be quickly solved in your mind. Practice similar questions to realize how you will become much faster and efficient in your calculations.

Fractions to percent: Below examples are for quick conversion from fractions to percentages. math help 4 After the percentages, let us take a look at how the fractions can be changed to decimals. Do you feel you already know them? Well remember, we are trying to learn the metal math. Here is how you can convert them in your mind. Take a look at the following questions:

Fractions to decimals: Change the fraction 2/5 into a decimal number. Here the given fraction is 2/5. The mental math trick is, for changing any given fraction to decimal number try to have 10 or multiples of 10 in the denominator. Multiply the numerator and denominator if the fraction 2/5 by 2. Follow the diagram below: math help 5 Did you follow the method? This trick has limitation though it can only be applied to the numbers which get 10 or multiples of 10 in the denominator via multiplication. Let us look at more examples to perfect this method.


Convert 7/25 into a decimal number.

Look at the denominator here its 25, which can be changed to 100 on multiplication by 4. Hence multiplying and diving the given fraction by 4. Follow the diagram below, this needs to be visualized mentally.

math help 6

Therefore the fraction 7/25 can be written as 0.28 in the decimal form.

Let me share another branch of math, Algebra where mental math tricks can be applied.

Adding the exponents: Combine the expression 3x4 (x5) Here for the given expression we have multiplication between the same variable x which needs to be combined. Since the base variable is the same for the given exponents add the powers. Here is the rule: math help 7 Subtracting the exponents: Combine the expression 2x11/ x9. Here for the given expression we have division between the same variable x which needs to be combined. Since the base variable is the same for the given expressions subtract the exponents of x. Here is the rule: math help 8 Multiplying the exponents: Combine the expression (x3)5? Here for the given expression we can combine exponents of the variable x by multiplying since they are raised to the same base. Follow the diagram below: math help 9

Therefore, today we looked through different methods and examples for solving math mentally. Use these methods to solve different questions whenever and wherever applicable. For more info you can chat with live math tutor online and get your math assignment help from amazing math tutors.

9 Must Know Methods for Solving Math Problems

Math has many topics and there are various kinds of questions related to each given topic. To solve a given math problem different kinds of methods and formulas can be used. Today, we will try to learn and understand 9 most basic and useful methods utilized while solving Math questions. Let us get started:

1. Method for calculating the LCM (Least Common Multiple)

Finding the least common multiple for the given numbers. I am pretty sure most of you have observed that LCM are part of problem solving for no matter which math topic you are working on. We need to calculate the LCM’s in simple topics like fractions, decimals and they may be also required to be calculated while solving questions in algebra, geometry and many more. Follow the example below:

What is the LCM of the two numbers 6 and 15?

For finding the LCM (least common multiple) first write the multiples for the given numbers.

Remember the 6 times table? Yes! They are all the multiples of number 6, so you have 6, 12, 18, 24, 30…. .

Now the 15 times table, don’t worry you need to check only till you get the common multiple.

So you have 15, 30, 45……………..

Did it strike a bell? Well look below for more clarity:

LCM

Hence the LCM for 6 and 15 equals to 30. (Sometime there can be more than one common multiple, always pick the least number as the LCM.)

2. Method for calculating the GCF (Greatest Common Factor)

Following the LCM is another interesting method in number theory. You guessed it right! The GCF (The greatest common factor.) For finding the GCF the Tree diagram method is very common. Here is a question: Find the GCF for the numbers 21 and 35? The first step is to write the tree diagram for 21 and 35. Try to follow the tree diagram below: GCF Using this tree method, you will get 21 = 3 x 7 and 35 = 5 x 7. (Note: 1 is always a factor for any given number.) Here 7 is the common factor for 21 and 35, which can be written once as its repeating in both the numbers. The Greatest common factor includes the remaining factors from both the numbers as well. Do not forget to include the 5 and 7. Hence GCF for 21 and 35 equals 3 x 5 x 7 = 105. After the LCM and the GCF, let us look at the method for changing the decimal numbers into fractions. Follow the example carefully:

3. Method of converting the decimal numbers into fractions

Convert the given decimal number 0.3 into a fraction. Here given to us is a decimal number. Count the number of decimal places. The number 0.3 has only one decimal place. Now while changing into a fraction multiply the numerator and the denominator by 10 for every decimal place. Here, since there is only one decimal place multiply by 10. Try to follow the diagrams below: decimal numbers into fractions Hence 0.3 can also be written as 3/10.

4. Method for solving Unit and Total Price word problems

Time to solve a work problem on price and money:

Anna and Ben went to a park. Anna brought 3 balloons and Ben brought 2 balloons. Find the total amount of money spent if each balloon costs $0.25.

For the given question you need to first calculate the total number of balloons Anna and Ben brought = 2+ 3 = 5.

Now comes the crucial point the decimal multiplication. Each balloon costs $0.25, so 5 balloons costs 5 x 0.25. Need help? Look at the diagram below:

Total Price

Hence the total price spent by Anna and Ben = $ 0.75.

Well problem solving is incomplete without equations. The next few methods will help you solve equations.

5. Method for solving one step equation using Addition

Find the value of y in the equation y – 6 = 12?

In the given equation 6 is subtracted from y. So the reciprocal operation needs to be applied to the equation. Add 6 on both sides of the given equation. This gives:

one step equation using Addition

Hence, the value of y = 18.

6. Method for solving one step equation using Subtraction.

Find the value of x in the equation x + 30 = 150? In the given equation 30 is added to x. So the reciprocal operation needs to be applied to the equation. Subtract 30 on both sides of the given equation. This gives: equation using Subtraction Hence the value of x = 120.

7. Method for solving one step equation using Multiplication

Find the value of y in the equation y/2 = 7? In the given equation y is divided by 2. So the reciprocal operation needs to be applied to the equation. Multiply by 2 on both sides of the given equation. This gives: equation using Multiplication Hence the value of y = 14.

8. Method for solving one step equation using Division

Find the value of x in the equation 5x = 45.

The given question has the equation with one variable x. I believe, by now did you get a hold of this method? The reciprocal operation of multiplication is division. Divide both sides of the equation by 5. This gives:

equation using Division

Hence the answer to the given equation is x = 9.

9. Method for solving Expressions using substitution

Now, what if there is an expression with more than one variables and you need to find the value of the expression. Here is what needs to be done:

Evaluate the value for the expression 4x – y, when x = 1 and y = 2.

Here for this question the method of substitution can be applied. You are given the value of x = 1 and y = 2. Hence substitute the values in the given equation to solve the question.

Not really sure how! Try to follow the diagram below:

Expressions using substitution

Much better, isn’t it! So after substitution here is how the expression will look like: 4(1) – 2 = 4 – 2 = 2. Hence the solution = 2.

We are not done yet! These were just few methods to get you started on solving math problems. To know more chat with a live Math tutor online and get more interesting details about the topic.

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Tips for Helping Your Children with Math Homework

Math Homework HelpGetting your child to do their homework can be a lot like trying to pull teeth. There may be a whole lot of resistance from the child but be patient. Learning is about improving ourselves, and even children understand that. They are always going about learning new ways to make this easier, or more intriguing or most of all, fun! So let’s approach the process from that perspective, shall we?

No Pressure

Children often feel a lot of pressure from adults and adults do not even realize when to pump the brakes a bit, but that is all a part of human nature. Children of course do need to be pressured, but in a positive way. What really works to motivate anyone is to show the short-term or long-term benefit to what it is that you are trying to accomplish. If you go in guns blazing trying to force pressure the child into learning the topic and you become frustrated, your child will in turn notice the negativity right away and begin to decide that they are being judged. They are right.
So avoid this tactic. Try to be open and understanding of their own learning process. Explain the logic of math problems in a way that will show them those benefits, how math is all around us, whether we are gauging our speed driving to school, measuring ingredients for a delicious snack or meal or counting the school supplies that we need. Specific examples really help children appreciate why we need to understand the concepts in mathematics, even at a basic level. They will be more enthused by this method and seek new ways to solve problems with more advanced math. A lot of this is just all about attitude and mentality.

Visual and Practical Models Work

Math is taught with great success in many Asian countries and many believe it is because of the way in which students learn the concepts and make the transition. It has been revealed that more visual representation matters to the student when discussing anything from simple basic addition/subtraction/multiplication/division to fractions and beyond. When they make a visual connection to the data, their brain can begin quickly deconstructing the logic behind the problem.
Ask your child to work out the problem aloud with you so you know their line of reasoning as well. This will help you understand their approach so you can teach them some new tricks. Again, be patient. The respect factor is exponentially higher with children when you are on their level and are actually helpful in their eyes. You should also work problems out aloud with them and do the same with everyday scenarios in life as you are going along your day with your kids. Explain concepts in everyday tone and language and relate it back to those school math problems they were working on.

Be Involved

It may seem obvious that you need to be involved in your child’s education, but moreover, try to be involved in their actual math problems and other studies. Make it your problem too. They will be more studious when they feel it is a group activity or game. Make it fun for them if you can by creating mini milestones like a bonus fun game for every successful problem solved or for finishing their homework. Remember how flash cards worked? The more colorful the cards the better by the way.
Being involved in all aspects of a child’s life is a great way to keep them involved in positive life activities as well. Your child will feel supported and confident knowing that their parents are there for them to help them when things get really tough. In math, when a problem is tough to understand, they may feel comfort in knowing that Mom or Dad can help guide them through it so they may understand it better. This helps a child’s confidence and self-esteem like no other.

Rewarding the Triumph

Children; just like pets, wild animals and grown adult humans; need to see the immediate benefits to the work behind learning a new skill, one that may seem mundane or useless in the form of numbers, symbols or expressions on a piece of paper or computer tablet screen.
When your child solves a problem, be sure to remember to try to challenge them to think of a way that problem can be implemented in the real world, or even better their world! When the child begins to unravel mysteries, not only will it excite and motivate them, they will be rewarded with pride and wisdom. They are never too young to understand this!

Get Access to free math lessons and math homework help online from basic math to algebra, geometry and beyond with the best online math tutors. Students, parents, teachers find these lesson plans to be very useful.

9 Secrets To Know About Speed And Mental Math Tricks And Techniques

Math is definitely challenging but what makes learning math fun and interesting is that, there are some tricks and techniques which can actually make the calculations easy to solve. Today, we will try to learn some math tricks which can be applied in solving different kinds of questions.

Speed And Mental Math Tricks

Multiplying a given number by 2

We all know the 2 times table. But what if 2 is being multiplied to a bigger number, there is a trick to make the multiplication quick and accurate. Think about it, multiplying by 2 it is nothing but doubling the given quantity. So to speed the calculations the given number can be added twice instead of multiplying by 2. For example 6 x 2 = 12.

This can also be got by 6 + 6 = 12. Now, if there is 32 x 2 = 64. This can also be got by 32 + 32 = 64.

Now applying this trick to bigger numbers multiplied by 2.

Find the value of 98340 x 2?

One method is the usual way of multiplying the given number by 2. But let us solve the same question with the trick of addition:

math 1

Hence 98340 x 2 = 1,96,680

Multiplying numbers which are multiples of 10

Did you know 10 is a very interesting number when it comes to multiplication? For example, in a question you come across a calculation such as 23 x 10 all you need to do is place a one zero next to 23. That is 23 x 10 = 230.

Can this be applied to bigger numbers as well? Yes it can! Let us look at some more examples:

While multiplying, 45 and 50 one method would be the regular multiplication. By applying the trick here all that needs to be done is 45 x 50, first find the value of 45 x 5 = 225. Since there is 50 which is a multiple of 10 place a zero next to 225.

So we get 45 x 50 = 2250. Another example would be, 25 x 30. Here first do 25 x 3 = 75. Now since there is 30 place a zero next to 75. This gives 25 x 30 = 750

Question: Sam brought 19 boxes of candies. Each box contains 200 candy bars, find the total number of candy bars in all the boxes.

Number of boxes of candies Sam brought is 19. Each box contains 200 candy bars.

Hence the total number of candy bars equal = 19 x 200.

Try to follow the diagram below for the calculation:

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Multiplying a given number by 11

No matter what number is given to you multiplication with 11 can become quite simple, follow the trick here. Look at eleven, there are two 1’s. Now for example you have 14 x 11. First do 14 x 1 = 14 then to this add 140 which is 14 + 140 = 154?

So we get 14 x 11 = 154

Need a better idea? Follow the example below:

Find the value of 456 x 11?

Here first calculate 456 x 1 = 456 now add 4560 to it so you get 4560 + 456 = 5016

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Adding three or more digit numbers

In some questions, you may have had situations where more than 2 numbers need to be added, it can get more tedious if they are big numbers. Let me share a little secret that can make adding such numbers much easier. For example there is a word problem: Riya spent $ 112 on shoes, $ 216 on bag and $315 on books. Find the total amount of money Riya spent on all the items. Solution: For the given question, the total amount of money spent equals the sum of all the given individual prices = $ 112 + $ 216 + $ 315. Follow the trick here, rather than adding the individual number. Add the hundreds place first. Follow the solution: math 4

Squaring number ending in 5

This rule is applicable from 5 to 95 only (i.e., 5, 15, 25, 35, 45, 55, 65, 75, 65, 75, 85, 95.) and here is how it works! We have 5 x 5 = 25.

The trick is, for a number ending in 5 when squared always has to end in 25. So for a given number example 152 pick the tens place, which is 1. Now the number after 1 is 2. Multiply 1 x 2 = 2. Now place a 25 next to 2. We get 225.

Now for 25 x 25. Here, 2 is in the tens place. What is the number next to 2, 3. So do 2 x 3 = 6. Now place a 25 next to 6. We get, 25 x 25 = 625.

Let us follow the diagram for clarity, take 65 x 65.

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Hence 65 x 65 = 4225

Divisibility rule for number 2

Here is a quick mental math trick to find weather a given number is divisible by 2 or not just by looking at it. If a number is ending with an even number then it is divisible by 2.

What are all the even numbers between 0 and 9 (0, 2, 4, 6, and 8).

Look at an example: 48 here 8 is an even number so it is divisible by 2. Now 51 is not divisible by 2 as 1 is an odd number. Apply the same for big numbers.

Find out if 4576 is divisible by 2? Prove it!

Here 4576 is ending with number 6. Since 6 is an even number the given number is divisible by 2. Follow the diagram for a quick check:

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Divisibility rule for number 4

Now that you are familiar with the divisibility rule for 2. Let us quickly check the divisibility rule for number 4. When it comes to 4 always check whether the last 2 numbers are divisible by 4. Consider 324 here it’s clearly know that 24 is divisible by 4 so 324 will be divisible by 4. Now let me give you another example:

Find out whether 5608 is divisible by 4? Check your answer.

Here again use the trick and figure it your mind. 08 are the last two numbers of the given number. Since 08 is divisible by 4, 5608 is divisible by 4. Let’s check if we got it right look at the diagram below:

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Divisibility rule for number 5

Did your math calculations get faster on the divisibility part? Now let us follow the trick for checking divisibility with number 5. For number 5, the given number should end either with 0 or 5. Take an example of 560 it is divisible by 5 since its ending in 0. Whereas 432 is not divisible by 5 since its ending with 2 not 0 or 5. Look at the following question.

Find out if 890 is divisible by 5? Check your answer.

Here the given number 890 is ending in 0, so it is divisible by 5. Let us check the answer, follow the diagram below:

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Combining the like terms

Many students find adding and subtracting like terms very confusing. Let us look at a simple way of solving this kind of a question. Did you know there is a trick with which you can solve the combining like terms in your mind? Here is what can be done:

Consider a question for finding 5x + 6x.

A like term is a term which have the same variable. Here it is x. Now for adding 5x and 6x since x is the same, just find 5 + 6 = 11. Hence 5x + 6x = 11x.

Did you follow the solution? Follow the next example:

Find the value of 3x + 7x + 10x?

All that needs to be done is add the numbers and place the common variable x next to the sum. Take a look at the diagram below:

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Hence the solution is 20x.

Therefore, practice these tricks and apply them in your math calculations. You will be amazed how they will aid in speeding your calculations. If you still need help, chat with a Live Math Tutor Online Now!

Tips To Remember How Math Logarithmic Notation Works

Logarithms are really fun and interesting, but I have seen many students find changing logarithmic notation to exponential notation and vice versa quite confusing. Well here are some useful tips to make you remember that this conversion is simpler than you have expected.

The exponential form is where we have the base number multiplied according the exponent to get the answer. Here is an example from online math tutor:

When you multiply 2 four times you get 16. That is 2 x 2 x 2 x 2 = 16.

This can be written in the exponential form as 24 = 16. Let’s look deeper into this notation:

log1

Let’s now try to follow how we can convert the exponential notation to the logarithmic notation:

log2

As show above, both the exponential notation and the logarithmic notation have the same base number. Next, there is an exchange in the exponent and answer while writing it in the logarithmic notation.

This can be better understood with an example:

Convert 34 = 81 from an exponential notation to logarithmic notation.

Here 3 is the base number which will remain the same even in the logarithmic form.

We have 4 as the exponent and 81is the answer which can be written as:

log3

Did you get a little hold of this method? Good let me show you one more example:

Convert 52 = 25 from exponential form to logarithmic form.

Everyone likes the 5 times table, for some reason it’s quite easy to memorize.

Here observe 5 is the base number and 2 happens to be the exponent. Multiplying 5 x 5 gives 25 as the answer. Now converting the exponential form to logarithmic form:

4-1hp6teb

Taking a step further, let us now convert the logarithmic notation into exponential notation applying the same process backwards.

Convert log4 64 = 3 from logarithmic notation to exponential notation.

Here the given logarithmic notation can be changed to exponential notation by keeping the base number 4 the same. Follow the steps below:

log5

Hence the exponential notation for the given question is 43 = 64.

Good so far! Now, have you ever observed some logarithms written without a base?

For example, notations like log 5, log 16 or log 150. Are they really without any base number? The answer is NO! They have a base number which is 10 it’s called the common base.

Hence, logarithms with base number 10 are called common logarithms. This can be shown as below:

log6

Convert the given exponential form 103 = 1000 to logarithmic form?

Here we have the base number for the exponential form as 10, so the final answer will be a common logarithm. Hence we can write the given question into a logarithmic notation as follows:

log7

So the final answer is log (1000) = 3. [Not to forget it still has a base 10.]

Now you are familiar with the logarithmic notation and ready to change exponential notation into logarithmic notation. But remember logarithms does not stop here, these are just few useful tips to get you started with the logarithmic notation.

Read more – Solving Logarithmic Equations

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How to Solve Algebra Word Problems in 5 Steps

For solving Algebra word problems you need to use your logic and find out answers for the problem. Here are 5 steps that help you solve Algebra problems with ease

  1. Identify the problem
  2. Identify what you know
  3. Make a plan
  4. Carry out the plan
  5. Verify whether your answer makes sense

Step 1

Identify the problem

The steps for identifying the problem are

  • Express the problem question or statement.
  • Identify the unit of the final answer.
  • Express the problem question or statement.

You find Algebra word problems in the form of a question or statement.

Examples:

Question How many saplings Brown needs to plant? How many televisions Brenda needs to sell to earn $20000?

Statement Find the number of saplings Brown has to plant. Solve for the number of televisions Brenda has to sell to earn $20000.

  • Identify the final unit of the answer

After understanding the purpose of the word problem, try to find out in what unit the answer will be like miles, ounces, pesos, number of trees or number of televisions.

Example for step1

Christiana is making brownies to serve at the family picnic. If the recipe calls for 21/2 cups of cocoa to serve 4 people, how many cups will she need for 60 people who attend the picnic?

  • Identify the problem: how many cups Christiana needs if 60 people attend the picnic?
  • Identify the final unit of answer: Cups

 Step 2

Identify what you know

I need more information What information you have is not adequate and you need more information.

Example for step 2 

Sarah is carpeting a rectangular room in her house. The length of the room is(x+2) feet and the breadth of the room is (x-6) feet and the area of the room is 84 square feet. Find the length and width of the room. Identify what you know

  • Sarah is carpeting a rectangular room
  • The length of the room is x+2
  • The breadth of the room is x-6
  • The area of the room is 84 square feet.
  • The formula for the area of a rectangle is A=lw
  • I need to find x to find the length and breadth of the room.

Step 3

Make a plan

Methods of building your plan

  • Write down your plan
  • Talk about your plan
  • Make a table
  • Draw a bar graph, line or circle
  • Draw any other type of graph
  • Draw a picture

Example for step 3

The Damsels Theater expects 275 patrons every weekend per new movie. How many new movies they will show if they expect 2200 patrons this week end?

  • For every new movie, 275 patrons come to Damsels Theater
  • 1 movie     =275 patrons
  • 2movies =275*2=550 patrons
  • 3 movies=275*3=825 patrons
  • 275*number of movies=2200 or 275*m=2200(m represents the number of movies)
  • Solve for m to find the answer

Step 4

Carry out the plan

Verify whether the plan is sensible. Check whether you have not missed anything or did not approach the problem in the wrong manner.

Example for step 4

Ben and Jack run a combined distance of 28 miles. Ben runs three times as many miles as Jack. How many miles does Jack run?

The plan

  • B+J=28 where B represents the number of miles run by Ben and J represents the miles run by Jack.
  • B=3*J because Ben runs three times as many miles as Jack.
  • Replace B with 3*J in the equation B+J=28

Carry out the plan

  • 3*J+J=28
  • 4*J=28
  • Solve for J: J=7

Step 5

Verify whether your answer makes sense

In the last step you have two red flags that signal wrong answers

  • Your answer is too big or too small
  • The question remains unanswered

Example for step 5

John is driving from his house to his company. On Monday morning John drives 6 miles north on Peter’s road. Then he drives 8 miles east on Willie’s Road to reach his company. On Tuesday morning, John avoids Peter’s and Willie’s Roads. What is the difference between the number of miles John drives on Monday and Tuesday mornings?

John’s drive to his company resembles a right triangle. You can use Pythagorean Theorem.geometry10 miles is the answer

Verify whether your answer makes sense

No. The answer is the direct distance between John’s company and house. It is not the answer for the question what is the difference between the number of miles John drives on Monday and Tues day mornings?

Make a new plan

  • Find the direct distance
  • Add 6 miles and 8 miles to find the total distance traveled on Peter’s and Willie’s Roads
  • Find the difference between the numbers in steps 1 and 2
  • Distance between the company and house is 10 miles
  • Distance traveled on Peter’s and Willie’s Roads is 6+8=14miles
  • Difference between the numbers 14-10= 4 miles

The answer is correct as per arithmetic and it makes sense.

Doing Algebra word problems through step by step approach is logical easy and fun.

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